Answer by user645636 for On prime factors of odd perfect numbers
Probably, because in general they don't really seem to have much special in their factorization other than a very abstract form. ( like ex. Mersenne numbers of prime exponents do, which if you want to...
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Why is it so difficult to determine actual numerical values for prime factors of odd perfect numbers?Recall that, if $N$ is an odd perfect number, then Euler proved that it takes the form $N = q^k n^2$...
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